2n^2-92n+720=0

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Solution for 2n^2-92n+720=0 equation: 



2n^2-92n+720=0

a = 2; b = -92; c = +720;
Δ = b2-4ac
Δ = -922-4·2·720
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-52}{2*2}=\frac{40}{4}
=10
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+52}{2*2}=\frac{144}{4}
=36
$

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